A complex number is z=a+bi where a,b∈R and i2=−1. We call a=Re(z) the real part and b=Im(z) the imaginary part.
Arithmetic:(a+bi)+(c+di)=(a+c)+(b+d)i and (a+bi)(c+di)=(ac−bd)+(ad+bc)i.
Proposition 1.1 (Properties of Complex Arithmetic). For all z,w∈C:
z+w=w+z and zw=wz (commutativity)
(z+w)+u=z+(w+u) and (zw)u=z(wu) (associativity)
z(w+u)=zw+zu (distributivity)
There exist additive identity 0 and multiplicative identity 1.
Every z=0 has a multiplicative inverse z1=∣z∣2zˉ.
Remark. The complex field C cannot be ordered: there is no total ordering on C Compatible with the field operations. In particular, i2=−1 precludes any such ordering.
Definition. The complex conjugate of z=a+bi is zˉ=a−bi.
Proposition 1.2. For all z,w∈C:
z+w=zˉ+wˉ and zw=zˉwˉ
zzˉ=∣z∣2
z+zˉ=2Re(z) and z−zˉ=2iIm(z)
zˉˉ=z
Definition. The modulus (or absolute value) of z=a+bi is ∣z∣=a2+b2.
Proposition 1.3 (Modulus Properties). For all z,w∈C:
∣z∣≥0 with equality iff z=0
∣zw∣=∣z∣∣w∣
∣z+w∣≤∣z∣+∣w∣ (triangle inequality)
∣z∣−∣w∣≤∣z−w∣ (reverse triangle inequality)
Proof of (3).∣z+w∣2=(z+w)(zˉ+wˉ)=∣z∣2+zwˉ+zˉw+∣w∣2=∣z∣2+2Re(zwˉ)+∣w∣2≤∣z∣2+2∣z∣∣w∣+∣w∣2=(∣z∣+∣w∣)2. The inequality follows from Re(zwˉ)≤∣zwˉ∣=∣z∣∣w∣. ■
Proposition 1.5. De Moivre’s theorem holds for all integers nIncluding negative values.
Proof. For n≥0It follows by induction from the multiplication law eiαeiβ=ei(α+β). For n<0Write n=−m with m>0: (cosθ+isinθ)n=(cosθ+isinθ)m1=cos(mθ)+isin(mθ)1=cos(−mθ)+isin(−mθ)=cos(nθ)+isin(nθ). ■
The n-th roots of unity are the solutions of zn=1:
zk=e2πik/n,k=0,1,…,n−1
They form a regular n-gon on the unit circle in the complex plane.
Proposition 1.7. If ω=e2πi/n is a primitive n-th root of unity, then ∑k=0n−1ωk=0 and ∑k=0n−1ωjk=0 for any j not divisible by n.
Proof. The sum ∑k=0n−1ωk=1−ω1−ωn=1−ω1−1=0 Provided ω=1. For j not divisible by n, ωj is a non-trivial root of unity, So the same argument applies. ■
Solution
Problem. Find all cube roots of −8.
−8=8eiπ. The cube roots are: zk=81/3ei(π+2πk)/3=2ei(π+2πk)/3 for k=0,1,2.
Complex numbers solve the problem that x2=−1 has no real solution: we directly declare that i exists and build the algebra on top of it. The key insight is that complex numbers are two-dimensional — each one is a point in the plane, not a point on a line. Addition is vector addition; multiplication combines scaling and rotation. The modulus measures distance from the origin, and the argument measures angle. Polar form reiθ makes multiplication natural: multiply the magnitudes and add the angles. Euler’s formula eiθ=cosθ+isinθ bridges exponential and trigonometric functions, revealing that complex exponentials trace circles.
Mistake 1: Assuming that complex numbers can be ordered. There is no total ordering on C compatible with the field operations. You cannot say i>0 or i<0 because i2=−1 would then imply −1>0 or −1<0, both of which contradict the ordering axioms. Never attempt to compare complex numbers using inequalities.
Mistake 2: Confusing the complex conjugate with the reciprocal. The complex conjugate zˉ=a−bi is not the same as the reciprocal 1/z=zˉ/∣z∣2. For example, if z=3+4i, then zˉ=3−4i but 1/z=(3−4i)/25. The conjugate reflects across the real axis, while the reciprocal also scales by 1/∣z∣2.
Mistake 3: Forgetting that ∣z∣2=zzˉ, not z2. The modulus squared is ∣z∣2=a2+b2=zzˉ. Do not confuse this with z2=(a+bi)2=a2−b2+2abi, which is a complex number as a rule. The modulus is always real and non-negative.
Mistake 4: Assuming that z1z2=z1z2 for complex numbers. This property holds for non-negative real numbers but fails for complex numbers as a rule. For example, (−1)(−1)=1=1, but −1−1=i⋅i=−1. Be careful with branch cuts when taking square roots of complex numbers.
Mistake 5: Confusing the argument of a complex number with a unique value. The argument arg(z) is multi-valued: if θ is an argument, then so is θ+2πk for any integer k. The principal argument Arg(z) is defined to be in (−π,π], but be careful when adding or subtracting arguments, as the result may need to be adjusted by 2π.